Q: Are cathode followers gain stages? 阴极跟随电路也是增益级吗?
A: Yes. 是。However, the problem is that people associate "gain stages" with, well...gain. 在人们印象里,也许增益这个概念并不明确 The cathode follower has a maximum theoretical gain of unity, and typically a gain of around 0.5 to 0.7 or so. 阴极跟随器在理论上电压增益小于1,只有0.5 – 0.7 的电压增益。To us engineering types, a gain of less than unity is still called a gain (that is, unless it's called a loss or an attenuation, in which case the attenuation is the reciprocal of the gain), so a stage with a gain of unity still has a gain - a gain of 1.对于一个工程技术人员来说,增益小于一也是增益,只不过是负增益而已,或者称之为损耗、衰减等等。 The cathode follower *is* an amplifier stage, but not a voltage amplifier in the typical sense.阴极跟随是一种放大电路,只不过不是我们普通概念上的电压增益级 It is used as a "buffer" amplifier, which means it has a high input impedance and a low output impedance.这是一种缓冲电路,具有高输入阻抗和低输出阻抗。 This means it does not appreciably load the previous stage it is connected to, and the very low output impedance allows it to drive low impedance loads without much signal voltage loss.它可以不需要精确计算和调整前后级的阻抗
,就可以自动进行匹配和驱动,而不损失电压增益。 For example, if the previous stage had an output impedance of 100K, and you tried to connect a stage with a 10K input impedance to it, you would only get 9% of your original signal when you connected the second stage, because of the voltage divider formed by the 100K output impedance and the 10K input impedance. 举例来说,一个100K的输出源要带动一个10K输入阻抗的放大级,将会损失90%的有效信号电压,因为阻抗不匹配。 If you insert a cathode follower with a 1K output impedance and a 1Meg input impedance, the 10K stage can be driven with 90% of the original signal, because there is now effectively a 1K:10K voltage divider instead of a 100K:10K voltage divider. 如果你在这两级之间插入输入阻抗1M输出阻抗1K的阴极跟随电路作为缓冲, 那么只需要90%的源信号就足以驱动后级放大器。The cathode follower is basically an active "impedance transformer", in this sense.从这种意义上说,阴极跟随电路是一种有源的阻抗匹配变压器。 The reason the cathode follower is used in driving a tone stack is not only because the tone control network impedance is relatively low in comparison to the output impedance of the previous stage, so it would cause a loss of gain, but more importantly, the tone stack is a filter network that is designed to ideally be driven from a zero source impedance to achieve it's proper frequency response.在吉他音箱的音调调整电路里使用阴极跟随器,不仅仅是用于阻抗匹配缓冲,更重要的理由是,音调调整本来目的就是要在没有输入信号损失的情况下,改变电路的频率响应特性。 The cathode follower provides a very low source impedance that allows the tone stack to work as designed. 使用阴极跟随器可以使之在损耗很小一部分信号功率的情况下达到这个目的。If the tone stack is driven from too large a source impedance, not only will there be a loss of gain, but there will be a different frequency response to the network, typically quite a few dB loss of the highs.如果音调调整电路都将吸收很多信号功率,那么损失的不仅仅是整机增益,还可能会使整体的高频部分响应特性变糟。 The cathode follower prevents this loss, allowing the tone stack to retain more of it's theoretical frequency response. 阴极跟随器则保证了这部分电路的正常工作。 Q: Does cathode biasing mean class A? 阴极偏压是不是意味着A类放大?
A: Absolutely not. You can have a cathode-biased class AB or class A amplifier, just as you can have a fixed-bias class A or class AB amplifier. 当然不是了,你可以同时拥有一台阴极偏压的A或AB类音箱,或者固定栅偏压的A或AB类音箱。 Q: Is it true that the only true class A amplifier is a single-ended amplifier? 是不是只有真正的A类放大器才是单端放大器?
A: No. You can design a true class A single-ended or push-pull amplifier. 不是的。你可以设计一个A类的SEPP放大器。 The presence of a phase inverter tube does not automatically mean the amplifier is class AB, just as the presence of a cathode resistor doesn't automatically mean the amplifier is class A.具有倒相电子管并不说明这是AB类放大器,就像使用阴极偏压电阻并不意味着这就是A类放大器一样。 It is all a function of where the output tubes are biased, and under what voltage/impedance conditions they are operating. 这只取决于输出级电子管的工作状态及其偏压情况而定。 In fact, unless you know the plate voltage, plate bias current, and output transformer reflected impedance, you can't tell the class of an amplifier just by looking at the schematic.事实上只看电路图是看不出来什么的,除非具体知道屏压、屏流以及输出变压器阻抗。 A push-pull class A amplifier differs from a single-ended class A amplifier tonally in that it cancels even-order harmonics generated in the output stage (but passes through even harmonics generated in the preamp stages, of course).一个A类推挽的音色明显有别于A类单端的音色,因为它能够减少偶次谐波 It also has inherent power supply rejection for lower hum and noise levels than a single-ended class A amplifier. 还对高压电源有更小的干扰,也因此噪音更低 Typically, a push-pull class A amplifier will clip rather symmetrically, while a single-ended class A amplifier usually clips asymmetrically, most often rounded on one side while hard-clipped on the other. 一个A类推挽动态范围也比A类单端更对称,因此不易发生消波失真。 While both amps are indeed true class A amplifiers, their tones are dramatically different. 尽管他们都属于A类放大器,但是音色上却差别很大。 This further illustrates the fact that there is really no such thing as a "class A" tone. 所以也不听某些人所说的“A类放大”音色,那是错误的概念。 Q: Are class AB amplifiers actually running in class A at lower volumes, as is commonly claimed? 是不是AB类放大器在小音量运行的情况下就成了A类放大器?
A: No. 怎么可能。 They are operating in conditions similar to class A, but they are not actually "class A at lower volumes". AB类在
小音量下确实接近A类放大器,但是绝不等同于A类小音量。 Now, what are the differences, you might ask?也许你现在要为区别在哪
Well, for one, the Class AB amplifier is biased in a more non-linear portion of the characteristic curves, which means it has more harmonic distortion than a true class A amplifier, even when running "clean". 首先一点,AB类放大电路的偏压更接近于伏安特性曲线的非线性部分,因而比A类放大器会有更多的谐波失真,即使是 CLEAN 档也会有失真。 Also, the efficiency will be greater than is theoretically possible with a class A amplifier at these levels. 另外,AB类的效率也比A类放大器高出许多。 There is a very real difference in tone and operating conditions between a true class A 10W amplifier running at say, 1W, and a 10W class AB amplifier running at 1W. 10瓦A类在1瓦运行跟10瓦AB类1瓦运行时的音色真的是完全不一样的 Same output level, same overall power level,but a different class of operation, different amount of distortion, different efficiency, and a different tone, even though neither one of them is in cutoff for any portion of the output cycle at that low level. 同样的输出功率,同样的总功率,但是由于电路不同,失真度就不一样,效率不一样,音色也不一样,甚至他们都在未发生消波失真之前就是这样了。 This is due to the bias point differences and load line differences.这是由于偏置点的不同以及负载线的不同而引起的。 The differences become even more apparent when the amplifiers are run at their full undistorted output power.在满功率不指失真输出时,这种差别将更明显。 The true class A amplifier will have no crossover distortion, while the class AB amplifier will. AB类放大器有交越失真而A类放大器没有。 The average plate current for the true class A amplifier will not change, or will change very little, from idle to full output power, while the average plate current in a class AB amplifier will increase dramatically. A类放大器的平均屏流基本不因输出功率而改变,AB类放大器的输出管屏流在不同的输出功率下差别巨大。 This will lead to "sag" in the power supply that doesn't exist in the true class A amplifier, which again results in a tonal change.因此A类不会发生电源电压因输出功率而变化的情况,因而导致音色的变化。
Q: Take a single EL34. The RCA manual says the maximum plate dissipation is 25 watts. Put the plate voltage at 400V. Set the bias so that the current is 60mA (24 watts dissipation). Put the plate voltage at 300V. Set the bias so that the current is 80mA. Both give you a dissipation of 24 watts. Both seem to be within operating parameters for this tube, but I'm guessing the tube is going to have a different effect on the signal. Is there a basic, overview explanation on how the tube is going to operate under these two conditions? 就拿EL34 来说吧,RCA手册说它的最大屏极热耗散为25瓦,那么在屏压400V屏流设置为60mA时屏极热耗散为24瓦,屏压300V屏流设置80mA是热耗散也是24瓦。这两种情况下看起来电子管工作状态相同,但是实际的使用效果却很不一样。你对此如何解释?
A: You cannot bias an amp at any arbitrary voltage for maximum dissipation, and expect to end up with a properly operating class A amp.你不能以最大屏极热耗散作为基准,随便取一个屏压就设置电子管到最佳的A类放大状态。 While the amplifier is biased at idle to a point not exceeding the plate dissipation, which seems okay on the surface, this is only half the story. 虽然电子管的静态屏极热耗散并没有超过极限值,看起来完全没有问题,但是这只是故事的一半而已。 When you put a signal into the amp, the plate dissipation changes from the idle value. 当吉他功放接收到输入信号以后,屏极热耗散将会偏离静态工作点。It can either go up, down, or stay the same, depending on the idle bias point. 它可能大,可能小,也可能不变,这取决于栅极偏置电压。 This is because the plate dissipation is dependent on the average signal at the plate, along with the plate voltage, idle bias current, and plate load impedance. 这是因为决定屏极热耗散的因素很多,包括屏压,静态屏流以及屏极负载阻抗。 If the tube is biased so that it just hits plate current cutoff/saturation on top and bottom at the same time, the tube is said to be operating at the limit of class A operation.电子管偏压保证它的静态工作点正好在截止/饱和居中位置的时候,我们称它工作在A类放大状态。 The average current draw at full signal will be the same as the average current draw at idle with no signal applied.这个时候,屏极的静态工作平均电流应该等于最大输入信号时候的平均电流
。 This is because the average value of the unclipped, full power output sine wave is zero - there is an equal area above the center as there is below the center of the waveform. 这一点很好理解,一列理想正弦波的输出平均值是0,因为上下半波的绝对值相等而符号相反而抵消了. This "ideal" symmetrical bias point can only be achieved at one plate voltage, if the constraint of biasing to exactly max dissipation at idle is applied.这种理想状态下,你当然可以选取静态工作点在屏极最大热耗散状态。 It is interesting to note that the plate dissipation will actually drop at full power, compared to idle, because the plate dissipation is equal to the DC input power minus the output signal power, which can be at most equal to 1/2 the idle DC input power.注意屏极的静态热耗散将在施加信号以后降低,因为在理想状态下,屏极动态热功率是总输入功率减掉输出负载功率的。负载功率平均值一般是总输入功率的一半。 Essentially, the part of the DC input power that is not passed on to the load must be dissipated as heat in the plate of the tube. 实际上,所有输入功率如果没有转化成输出负载功率的话,都将成为电子管屏极的热损耗功率。 In a true class A amplifier at idle, no power is developed in the load, so all the power is dissipated in the tube.在A类放大的静态工作点,由于没有输出功率,所有的输入功率全部转化成热量耗散在屏极。 At full output power (unclipped sine wave), half the DC input power is used to produce the AC output signal, the other half is dissipated as heat in the tube. 在最大不失真输出的情况下,一半输出,一半转变成热量耗散在屏极。 Now, if you bias that same tube to max dissipation at a significantly higher voltage/lower current point, it will again be okay at idle, because it isn't exceeding the max dissipation rating for the tube.迄今为止,你把静态工作点设置为电子管最大屏极热耗散点还是没有错。 However, when a signal is applied, the tube will reach saturation before it reaches cutoff on the other side, so the average area above the zero bias line will be larger than the average area below the zero bias line, even when the tube is not clipped on top or bottom.但是加上输入信号以后,电子管通常都是先达到饱和点,后达到截止点的。也就是说,交流输入信号的高电平部分电压一般是要比低电平电压来得多一些,尽管这时候电子管还没有发生截止或者饱和。 This results in a net average increase in plate dissipation over the no-signal bias point. 这就会造成动态屏极热损耗高于静态。The tube, which was perfectly happy at idle, may now exceeding the max plate dissipation with a signal applied, and the plates may start to glow red when you start playing, and go back to normal when you stop playing.这样设置屏极偏流的电子管会在你开始弹奏吉他以后,屏极慢慢发红,当你停止弹奏后再慢慢复原。 If you were to use cathode bias instead of fixed bias, the increase in average plate current will cause an increase in cathode voltage, which will act to reduce the plate current and counteract the increase in dissipation, at the expense of a shift in operating point.如果你是使用阴极电阻偏压的方式,增加的屏流也就是阴极电流会导致阴极电压升高,这是一个负反馈过程,反过来降低屏极电流以及热耗散,但是原来的静态工作点会发生很大的偏移。
If you were to bias the tube to a lower idle dissipation, say 70% of the max dissipation, the increase in plate dissipation that occurs at max signal is now offset by the lower average idle dissipation, so the tube is again operating in a safe area at all times. 如果你降额使用,比方说屏极热耗散只有极限值的70%,就不会有任何问题了。 In this case, however, you no longer have a true class A amplifier, because the plate current will go into cutoff at some point before it hits saturation on the other side, because the bias is offset relative to the available grid swing.在这种情况下,理论上放大器不再是一个A类放大器,因为静态工作点不是正中心点,而是偏下一些,屏流会先达到截止后达到饱和。 The tube has now been biased to class AB operation.理论上说这是一种AB类放大状态。 This may be fine for a single-ended amp, provided that you don't mind a bit of asymmetrical clipping when you drive the amp hard, which creates a predominant even-order harmonic structure.在单端放大电路里,这根本对你没有什么影响,只有在你最使劲弹奏的时候会由于削波带来一些偶次谐波失真。 In the case of a push-pull amp, the other tube "takes over" when the first one goes into cutoff, so the output is not clipped, even though the plate current of the first tube has completely shut off for a portion of time. 在推挽电路里,由于对面电子管的补偿,则根本不会产生消波。即使其中一个电子管在完全截止的状态下也不会发生消波。 As mentioned earlier, there is a bias shift that can occur when the grid signal is AC-coupled into the tube through the typical coupling caps present in most guitar amplifiers.以前曾经提到过,大多数吉他功放都会因为栅极信号是通过电容交流耦合进来的,而发生偏置点漂移。 When the grid drive voltage exceeds the cathode voltage, the grid voltage is "clamped" at the peak to a point near the cathode voltage. 当栅极信号驱动电压超出了阴极电压的时候,信号会被阴极电位钳位而发生削波。 As the signal is increased, the peak stays at the same point, but the "center" of the grid drive signal is shifted downward.当信号输入电位继续升高,但是输出依然停留在原来位置,不过栅极驱动信号的中心点却发生了向下的漂移。 This changes the duty-cycle of the plate waveform, and therefore changes the average dissipation in the output tube, in a manner dependent on the magnitude of the applied signal. 这将会改变屏极波形的负载,继而改变屏极热耗散功率,而这又取决于输入信号的振幅。 You can use a load-line superimposed on the characteristics of the tube to determine the max plate voltage, idle current, and load impedance that will allow you to bias the tube to the optimum class A operating point.你可以把电子管的负载线、伏安特性曲线,静态屏流以及负载阻抗等等曲线叠加在一起,来决定如何把A类放大静态工作点偏置到最佳状态。 The aforementioned EL34 typically cannot be run at a plate voltage much higher than 250V without exceeding the "true" limiting class A operating range at reasonable distortion levels. 前面提及的EL34,如果在A类放大下,不产生难以忍受的失真,那么屏压就不应该超过250V。 You can run a "flatter" load line, i.e. higher impedance load, and colder bias up to a certain point to try and eke out as much symmetry as you can if you are using higher plate voltages. 你可以在更容易产生噪音的负载下提升屏压,比方说提高负载阻抗,降低栅极偏置。 The downside to this higher impedance load is increased harmonic distortion and nonlinearity at "clean" outputs, and higher plate voltage swings that may exceed tube maximum ratings or output transformer insulation ratings.提高变压器初级阻抗会带来谐波失真以及非线性失真,而更高的屏压也会增加高压击穿变压器的可能性。 For a better explanation of this, see this paper on biasing - The Last Word On Biasing.如果想知道得更多,你可以参考这篇文章中得另一篇专门关于栅极偏置的问答 —— 关于偏置的最后一句话。 |